Text Solution Solution : Given `p(x)=2x^4+7x^3−19x^2−14x+30`<br> Two of its zeroes are `sqrt(2) `and `−sqrt(2)`<br> so,`g(x)=(x−sqrt(2))(x+sqrt(2))`<br> or,`x^2−2`<br> so we get <br>,divisor=`x^2−2`<br> Quotient=`2x^2+7x−15`<br> Remainder=`0`<br> so,`q(x)=−2x^2+7x−15`<br> `2x^2+10x−3x−15=0`<br> =`2x(x+5)−3(x+5)=0`<br> =`(2x−3)(x+5)=0`<br> thus,`x=3/2,-5`<br>so,roots of equation is `sqrt(2) ,−sqrt(2) ,3/2 ` and `−5` Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now
Verify that the numbers given alongside of the cubic polynomials below are their zeroes. Also, verify the relationship between the zeroes and coefficients in each case: Let p(x) = 2x3+x2–5x + 2 Comparing the given polynomial with ax3 + bx3 + cx + d, we get Now,
and ∴ are the zeroes of Hence, verified.Here, we have Now, and Hence verified. |