A real and inverted image of the same size is formed by a convex lens when the object is placed

There are six possibilities of position of object in the case of convex lens:

Object at infinity:

Convex lens converge parallel rays coming from objet at infinity and a highly diminished - point sized, real and inverted image is formed at principal focus F2.

A real and inverted image of the same size is formed by a convex lens when the object is placed

Fig: Object at Infinity

Properties of Image: Image is highly diminished, real and inverted.

Object beyond C1 or 2F1Centre of Curvature

A diminished, real and inverted image is formed between principal focus, F2 and centre of curvature, C2 at the opposite side when an object is placed beyond C1 of a convex lens.

A real and inverted image of the same size is formed by a convex lens when the object is placed

Fig: Object Beyond 2F

Properties of Image: Image is diminished, real and inverted.

Object at CCentre of Curvature

A same sized, real and inverted image is formed at centre of curvature, C2 when object is placed at centre of curvature, C1 of a convex lens.

A real and inverted image of the same size is formed by a convex lens when the object is placed

Fig: Object at 2F

Properties of Image: Image is same size as object, real and inverted.

Object between C and F

An enlarged, real and inverted image is formed beyond centre of curvature, C2 when an object is placed between centre of curvature, C1 and principal focus, F1 of a convex lens.

A real and inverted image of the same size is formed by a convex lens when the object is placed

Fig: Object between 2F and F

Properties of Image: Image is enlarged, real and inverted.

Object at Focus F1

An infinitely large, real and inverted image is formed at infinity when object is placed at principal focus, F1 of a convex lens.

A real and inverted image of the same size is formed by a convex lens when the object is placed

Fig: Object at F

Properties of Image: Image is highly enlarged, real and inverted.

Between F1 and O

A virtual, erect and enlarged image is formed at the same side of lens, when an object is placed between principal focus, F1 and optical centre, O of a convex lens.

A real and inverted image of the same size is formed by a convex lens when the object is placed

Fig: Object between F and O

Properties of Image: Image is enlarged, virtual and erect.

Summary of Image Formation

Object at InfinityImage is formed at focus. Image is real, inverted and highly diminished in size.
Beyond CImage is formed between F2 and 2F2. Image is real, inverted and smaller than object.
Between C and FImage is formed beyond C2 or 2F2. Image is real, inverted and larger than object.
At CImage is formed at 2F2 or C2. Image is real, inverted and of same size as object.
At FImage is formed at infinity. Image is real, inverted and highly enlarged.
Between F and OImage is formed on 2F1. Image is virtual, erect and larger than object.

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Option 3 : At twice the focal length

A real and inverted image of the same size is formed by a convex lens when the object is placed

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A real and inverted image of the same size is formed by a convex lens when the object is placed

CONCEPT:

  • The transparent curved surface which is used to refract the light and make an image of any object placed in front of it is called a lens.
    • The lens whose refracting surface is upside is called a convex lens and the lens whose refracting surface is inside is called a concave lens or diverging lens.
    • The convex lens is also called a converging lens.

EXPLANATION:

  • When the object is placed at twice the focal length distance from the optical center on the principal axis of a convex lens, a real and inverted image of the same size is obtained.

ALTERNATE SOLUTION:

Analytically,

  • The focal length of the convex lens can be calculated by 

\(⇒ f = \frac{{m\left( {u + v} \right)}}{{{{(1 + m)}^2}}}\)

Where, m = magnification (in this case m = 1),

u = object distance,

v = image distance (in this case u = v), and

f = focal length

\(⇒ f = \frac{{1 \times \left( {u + u} \right)}}{{{{(1 + 1)}^2}}}\)

\(⇒ f = \frac{{2u}}{{{2^2}}}\)

⇒ u = 2f

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