25 joule of work is done in moving a charge of 5c across two points A and B

A work of 25 J and 30 J is done when 5 C charge is moved first to point A and then to point B from infinity. Calculate the potential difference between points A and B.

WA = 25 J; WB = 30 J

Work done to move the 5C charge from A to B = WB - WA 

W = 30 - 26 = 5 J

Charge Q = 5 C

Potential difference between A and B

V = `"W"/"Q" = 5/5 = 1` V

V = 1 volt

OR

WA = 25 J

WB = 30 J, charge = Q = 5 C

Potential at point A = V1 = `"W"_"A"/"Q"`

V1 = `25/5 = 5` volt

Potential at point B = V2 = `"W"_"B"/"Q"`

V2 = `30/5 = 6`volt

Potential difference A and B = V = V2 - V1 

V = 6 - 5 = 1 volt

Concept: Earth’s Magnetism

  Is there an error in this question or solution?

Text Solution

Solution : Given, work done , w = 20 J and charge q = 5 C <br> `:.` The pontential differene between the points, <br> `DeltaV = (w)/(q) = (20 J)/(5 C) = 4` volt.

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The correct answer is 55 J.

Given,

charge, Q= 5C

Potential difference, V= 11V

W= Q*V

   =  5*11

   = 55 J

• Potential Difference:
  • Work done in bringing a unit positive charge from one point to another point is the potential difference between the two points.
  • Its SI unit is volt.
  • It is a scalar quantity.

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