We need to find where will the hour hand of a clock stop for the given set of questions Consider clock to be 360° and the clock marks up to 12 360/12 = 30 degrees per hour
(a) From 6 and turns through 1 right angle?
6 o’ clock = 6 X 30 = 180 °
From 180, a turn of right angle
180+90/ 30= 270/30= 9
So the hour hand would be at 9
(b) If the hour hand of a clock starts from 8 and turns through 2 right angle
8 o’clock = 8* 30° = 240°
240+2*90= 240+180= 420°
420/30= 14
We know that as per 24-hour format 14:oo hours stands for 2 o’clock
So, the hour hand would be at 2 o’clock
(c) If the hour hand of a clock starts from 10 and turns through 3 right angle
10 o’clock = 10* 30° = 300°
300+ 3*90 = 570/30 = 19
We know that as per 24-hour format 19:oo hours stands for 7 o’clock
So, the hour hand would be at 7 o’clock
(d) If the hour hand of a clock starts from 7 and turns through 2 straight angles, then it will stop at 7
7 o’ clock = 7* 30 = 210 °
210+ 2 * 180 = 210+360 = 570/30= 19
We know that as per 24-hour format 19:oo hours stands for 7 o’clock
So, the hour hand would be at 7 o’clock
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