When the sun is 30º above the horizontal, Find the length of shadow cast by a building 50m high
Let AB be the building and AC be its shadow.
Then, AB = 50 m and θ = 30º.
`\therefore \frac{AC}{AB}=\text{cot 3}0^\text{o}=\sqrt{3}`
`\Rightarrow \frac{AC}{50}=\sqrt{3}`
⇒ AC = 50√3 cm.
Concept: Heights and Distances
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