What is the derivative of PI 4?

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If $y=\pi^2$, then $dy/dx=2\pi$

Is this statement true or false? If false, correct the statement.

My answer to this question is false because $y=\pi^2$, there is no variable.

I like to know if my answer is correct, and I would appreciate explanation.

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HomeDerivative[Solved] What is the Derivative of pi/4?

Derivative of Pi/4

Answer: The derivative of pi/4 is 0.

We know that the value of the number `\pi` is approximately equal to 3.1416 (up to `4` decimal places). Also, the number `\pi` is irrational.

Note that the value of `\pi` is determined by the area of a unit circle (that is, a circle of radius 1). As the area of a unit circle is fixed, so we conclude that `\pi` is a fixed number. 

`\Rightarrow \pi` is a constant. 

`\Rightarrow \pi/4` is a constant. 

So `\pi/4` does not change with respect to any variable.

`\therefore d/dx(\pi/4)=0` by the rule Derivative of a constant is 0.

Thus, the derivative of `\pi/4` is equal to `0`.

Let `f(x)=\pi/4`. As both `\pi` and `4` are constants, the quotient `\pi/4` is independent of `x`. Thus, we have 

`f(x+h)=\pi/4` for any values of `x` and `h`. 

Now, by the first principle, the derivative of `f(x)` is equal to

`d/dx(f(x))` `=\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}`

In this formula, we put `f(x)=\pi/4`. 

Hence `d/dx(\pi/4)` `=\lim_{h \to 0} \frac{\pi/4 -\pi/4}{h}`

Thus, the derivative of  `\pi/4` from the first principle, that is, by the limit definition is equal to `0`.