What is the angle subtended at the centre of a circle of radius 10 cm by an arc of length 5π cm

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Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length (5π/3) cm.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length 5 π / 3 cm.

We know that the arc length l of a sector of an angle θ in a circle of radius r is

It is given that

and length . Substituting these value in above equation,

Hence, the angle subtended at the centre of circle is

.

Find, in terms of π, the length of the arc that subtends an angle of 30° at the centre of a circle of radius 4 cm.Find the angle subtended at the centre of a circle of radius 'a' by an arc of length (aπ/4) cm.An arc of length 20π cm subtends an angle of 144° at the centre of a circle. Find the radius of the circle.AB is a chord of a circle with centre O and radius 4 cm. AB is of length 4 cm. Find the area of the sector of the circle formed by chord AB.A sector of a circle of radius 4 cm contains an angle of 30°. Find the area of the sector.