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We have
`r=6cm`
length of the arc=`3pi cm`
We will find the angle subtended at the centre of a circle.
Length of the arc=`θ/360xx2pi r`
Substituting the values we get,
3pi=`θ/360xx2pixx6 ` ............(1)
Now we will simplify the equation (1) as below,
` 3pi=θ/360xx2pixx6`..........(1)
`3pi=θ/30xxpi`
`3=θ/30`
`⇒ θ=90°`
Therefore, angle subtended at the centre of the circle is `90°`
Page 2
We have
`r=5 cm`
length of the arc(l)=3.5 cm
Now we will find the area of the sector.
Area of the sector=`1/2xxlr`
Substituting the values we get,
Area of the sector=`1/2xx3.5xx5`..........(1)
Now we will simplify the equation (1) as below,
Area of the sectors=`1/2xx17.5`
Area of the sectors=`8.75`
Therefore, area of the sector is `8.75 cm^2`