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Two supplementary angles are in the ratio 4 : 5. Find the angles.
Supplementary angles are in the ratio 4 : 5
Let the angles be 4x and 5x
It is given that they are supplementary angles
∴ 4x + 5x = 180°x
⇒ 9x = 180°
⇒ x = 20°
Hence, 4x = 4 (20) = 80°
5( x) = 5(20) = 100°
∴ Angles are 80° and 100°
Is there an error in this question or solution?
Page 2
Two supplementary angles differ by 48°. Find the angles.
Given that two supplementary angles are differ by 48°
Let the angle measured is x°
∴ Its supplementary angle will be (180 - x)°
It is given that
(180 - x) - x = 98°
⇒ 180 - 48° = 2x
⇒ 132 = 2x
⇒ x = `132/2`
⇒ x = 66°
Hence, 180 - x = 114°
Therefore, angles are 66° and 114°
Is there an error in this question or solution?
Two supplementary angles are in ratio 5 : 4. Find the angles
Let the angles be 5x and 4x
According to the problem
5x + 4x = 180°
9x = 180°
x = `(180^circ)/9`
x = 20°
∴ Two angles are
(i) 5x = 5 × 20° = 100°
(ii) 4x = 4 × 20° = 80°
Concept: Related Angles - Supplementary Angles
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