The sum of the lower limit of the modal class and upper limit of the median class is

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 Here, N = 66.

\[\therefore \frac{N}{2} = 33\] , which lies in the interval 10–15.So, the lower limit of the median class is 10.The highest frequency is 20, which lies in the interval 15–20.Therefore, the lower limit of modal class is 15.

So, the required sum is 10 + 15 = 25.

The sum of lower limit and upper limit of modal class is& 10 & 16 & 25 & 16 & 20Whline lendarray

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