Distribution
0-5
5-10
10-15
15-20
20-25
Frequency
10
15
12
20
9
As per the given data the let us calculate the cumulative frequency:
Distribution | 0-5 | 5-10 | 10-15 | 15-20 | 20-25 |
Frequency | 10 | 15 | 12 | 20 | 9 |
Cumulative frequency | 10 | 25 | 37 | 57 | 66 |
The lower limits of the median class:
Here n is even; then the median is given by the mean of (n/2)th observation
\(\begin{array}{l}\frac{N}{2}\end{array} \)
⇒
\(\begin{array}{l}\frac{66}{2}\end{array} \)
= 33
As 37 is just greater than 33,
Therefore, the median class is ’10 – 15′.
The lower limits of the median class = 10
The lower limits of the modal class:
Modal class=modal class with maximum frequency.
Therefore, the modal class is 15 – 20.
The lower limit of the modal class is 15.
Sum of lower limits of median class and modal class=10 + 15 = 25
The lower limits of the modal class = 25
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10 Questions 10 Marks 6 Mins
Concept:
- The cumulative frequency is calculated by adding each frequency from a frequency distribution table to the sum of its predecessors.
- To find out the median class you have to find the value of N/2 and then find out the interval in which it lies, where N is the final cumulative frequency.
- The modal class is the group with the highest frequency.
Calculation:
Class | Frequency | Cumulative Frequency |
0-5 | 10 | 10 |
5-10 | 15 | 25 |
10-15 | 12 | 37 |
15-20 | 20 | 57 |
20-25 | 9 | 66 |
Here, N = 66
∴ N/2 = 33, which lies in the class interval 10-15.
So, the lower limit of the median class is 10.
Here, the highest frequency is 20, which lies in the class interval 15-20.
So, the lower limit of the modal class is 15.
So, the required sum is 10 + 15 = 25.
Hence, the sum of lower limits of the median class and modal class is 25.
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