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Question 1 Refer to the following partial ANOVA results from Excel (some information is missing). Picture The number of observations in the entire sample is Answer 20 19 22 1 points Question 2 Here is an Excel ANOVA table that summarizes the results of an experiment to assess the effects of ambient noise level and plant location on worker productivity. The test used a= 0.05. Picture Is the effect of plant location significant at a= .05? Answer Yes No Need more information to say 1 points Question 3 Using one-factor ANOVA with 30 observations we find at a= .05 that we cannot reject the null hypothesis of equal means. We increase the sample size from 30 observations to 60 observations and obtain the same value for the sample F test statistic. Which is correct? Answer We might now be able to reject the null hypothesis We surely must reject H0 for 60 observations C.We cannot reject H0 since we obtained the same F-value It is impossible to get the same F-value for n = 60 as for n = 30 1 points Question 4 What are the degrees of freedom for Tukey's test statistic for a one-factor ANOVA with with n1= 6, n2 = 6, n3 = 6? Answer 3, 6 6, 3 6, 15 3, 15 1 points Question 5 The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers. A random sample of three tax returns is chosen from each of three centers. The time (in days) required to process each return is recorded as shown below Picture The test to use to compare the means would require Answer Three-factor ANOVA One-factor ANOVA Two-factor ANOVA without replication Two-factor ANOVA with replication 1 points Question 6 Here is an Excel ANOVA table that summarizes the results of an experiment to assess the effects of ambient noise level and plant location on worker productivity. The test used a= 0.05. Picture Is the effect of noise level significant at a= .01? Answer Yes No Need more information to say 1 points Question 7 Refer to the following MegaStat output (some information is missing). The sample size was n = 65 in a one-factor ANOVA. Picture At a = .05, which is the critical value of the test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: this question requires a Tukey table. Answer 2.81 2.54 2.33 1.96 1 points Question 8 Refer to the following partial ANOVA results from Excel (some information is missing). The response variable was Y = maximum amount of water pumped from wells (gallons per minute). Picture The MS for interaction is Answer 7.25 8.17 8.37 9.28 1 points Question 9 Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table Picture The number of observations in the original sample was Answer 59 60 58 54 1 points Question 10 To compare the cost of three shipping methods, a random sample of four shipments is taken for each of three firms. The average cost per shipment is shown below. Picture In a one-factor ANOVA, degrees of freedom for the within-groups sum of squares will be Answer 11 3 9 2 1 points Question 11 Which is the Excel function to find the right-tail p-value for Fcalc = 4.52 with n1 = 15, n2 = 12? Answer =FDIST(4.52, 15, 12) =FINV(4.52, 14, 11) =FDIST(4.52, 14, 11) =FINV(4.52, 15, 12)
Refer to the following partial ANOVA results from Excel (some information is missing).
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Question 1
Refer to the following partial ANOVA results from Excel (some information is missing).
Picture The number of observations in the entire sample is
Answer
20
19
221 points
Question 2
Here is an Excel ANOVA table that summarizes the results of an experiment to assess the effects of ambient noise level and plant location on worker productivity. The test used a= 0.05.
Picture Is the effect of plant location significant at a= .05?
Answer
Yes
No
Need more information to say1 points
Question 3
Using one-factor ANOVA with 30 observations we find at a= .05 that we cannot reject the null hypothesis of equal means. We increase the sample size from 30 observations to 60 observations and obtain the same value for the sample F test statistic. Which is correct?
Answer
We might now be able to reject the null hypothesis
We surely must reject H0 for 60 observations
C.We cannot reject H0 since we obtained the same F-value
It is impossible to get the same F-value for n = 60 as for n = 301 points
Question 4
What are the degrees of freedom for Tukey’s test statistic for a one-factor ANOVA with with n1= 6, n2 = 6, n3 = 6?
Answer
3, 6
6, 3
6, 15
3, 151 points
Question 5
The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers. A random sample of three tax returns is chosen from each of three centers. The time (in days) required to process each return is recorded as shown below
Picture The test to use to compare the means would require
Answer
Three-factor ANOVA
One-factor ANOVA
Two-factor ANOVA without replication
Two-factor ANOVA with replication1 points
Question 6
Here is an Excel ANOVA table that summarizes the results of an experiment to assess the effects of ambient noise level and plant location on worker productivity. The test used a= 0.05.
Picture Is the effect of noise level significant at a= .01?
Answer
Yes
No
Need more information to say1 points
Question 7
Refer to the following MegaStat output (some information is missing). The sample size was n = 65 in a one-factor ANOVA.
Picture At a = .05, which is the critical value of the test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: this question requires a Tukey table.
Answer
2.81
2.54
2.33
1.961 points
Question 8
Refer to the following partial ANOVA results from Excel (some information is missing). The response variable was Y = maximum amount of water pumped from wells (gallons per minute).
Picture The MS for interaction is
Answer
7.25
8.17
8.37
9.281 points
Question 9
Refer to the following partial ANOVA results from Excel (some information is missing).
ANOVA Table
Picture The number of observations in the original sample was
Answer
59
60
58
541 points
Question 10
To compare the cost of three shipping methods, a random sample of four shipments is taken for each of three firms. The average cost per shipment is shown below.
Picture In a one-factor ANOVA, degrees of freedom for the within-groups sum of squares will be
Answer
11
3
9
21 points
Question 11
Which is the Excel function to find the right-tail p-value for Fcalc = 4.52 with n1 = 15, n2 = 12?
Answer
=FDIST(4.52, 15, 12)
=FINV(4.52, 14, 11)
=FDIST(4.52, 14, 11)
=FINV(4.52, 15, 12)
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Question “Refer to the following partial one-factor ANOVA results from excel (some information is missing. And you…”
- Refer to the following partial one-factor ANOVA results from
excel (some information is missing. And you need to work it out in
the questions below.) Now, the F statistic is equal to:
Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F statistic |
Between Groups | 210.2788 | |||
Within Groups | 1483 | 74.15 | ||
Total | 2113.833 |
- Referring to the table in question 1. The sum of squares for
between groups variation is:
- 129.99
- 630.83
- 1233.4
- We cannot tell from given information
- Referring to the table in question 1, the Degree of Freedom for
between groups variation is (hint: use the results from Q2 and the
mean square of between groups):
Using above ANOVA result we get,
i) The F statistic is.
F = MS Between and MS Within = 209.2788 / 2.84
Answer: d) 2.84
ii) The sum squares of between group variation (SS Between) is,
SS Between = SS SS Within = 2113.833 – 1483 = 630.833
Answer: b) 630.83
iii). Degrees of freedom for variation between groups ( DF Between)
DF Between = MS Between/ MS between = 603.83 / 209.2788 = 2.999
DF Between = “strongTag4$”
Answer: a) 3
DF Within = MS Within = 1483 / 20
DF Total = Df Between & DF Within = 2 + 20 = 23
Conclusion
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