Is the distance between the points 4 K and 10 is 5 then what can be the possible value of K?

5.

A number is chosen at random from the number –3, –2, –1, 0, 1, 2, 3. What will be the probability that square of this number is less then or equal to 1? 

S = {−3, −2, −1, 0, 1, 2, 3}Let E be the event of getting a number whose square is less than or equal to 1.So, E = {−1, 1, 0}P(E)=3/7.

Hence, the probability of getting a number whose square is less than or equal to is 3/7.

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If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?

Consider the points A(4, k) and B(1, 0).

It is given that the distance AB is 5 units.

By distance formula, disance AB is as follows:

`AB = sqrt((4-1)^2 + (k - 0)^2)`

`=> 5 = sqrt(9 + (k)^2)`

`=> 25 = 9 + k^2`

`=> 16 = k^2`

`=> +- 4 = k`

Hence, value of ka are `+- 4`

Concept: Distance Formula

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