The pictorial form of the given problem is as follows,
Pythagoras theorem states that in a right-angled triangle, the square on the hypotenuse is equal to the sum of the squares on the remaining two sides.
First, we consider the ΔABM and applying Pythagoras theorem we get,
AM2 = AB + BM2
AB2 = AM2 - BM2 ......(i)Now, we consider the ΔABC and applying Pythagoras theorem we get,
AC2 = AB2 + BC2
AB2 = AC2 - BC2 ......(ii)
From (i) and (ii) we get,
AM2 - BM2 = AC2 - BC2
AM2 + BC2 = AC2 + BM2
Hence Proved.
Yes it is a right angled triangle
statement:Because if square of one side is equal to the sum of the squares of the other two sides. Then the angle opposite to the first side is right angle.It is a right angled triangle
For example,
In triangle ABC,
AB,AC,BC are sides of a triangle
so if AB2=AC2+BC2
So it is a right angled triangle
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Jan 31, 2021
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August 24, 2022
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