If the ratio of amplitude of two waves is 4:3 then the ratio of maximum and minimum intensities is

Transcribed Image Text:4:3, then the ratio of maximum and minimum 0 1: If the ratio of amplitude of two waves is 4-3 then the ratio of maximum and minimum intensities is (a) 16:9 (b) 9: 16 om (c) 1:49 (d) 49:1

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Ratio of amplitude of two waves is 1: 16. The ratio of maximum to minimum intensity when the waves interfere is

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`16:18``18:16``49:1``1:49`

Answer : C

Solution : In the interference pattern, <br> `I_("max")=(a+b)^(2)and I_("min")=(a-b)^(2)` <br> `(I_("max"))/(I_("min"))=((a+b)^(2))/((a-b)^(2))=((4+3)^(2))/((4-3)^(2))` <br> `((7)/(1))^(2)=(49)/(1)=49:1`