# If one of the root of the quadratic equation px² 15x 14 0 is 2/3 find the value of p

 CBSE 10 - Maths Solve it Asked by navneetpra499 | 19 Jul, 2022, 05:06: AM ANSWERED BY EXPERT CBSE 10 - Maths answer this question Asked by anuragtikekar2006 | 07 May, 2022, 06:33: PM ANSWERED BY EXPERT CBSE 10 - Maths Ui Asked by Vadderamakrishna2 | 30 Aug, 2021, 12:17: PM ANSWERED BY EXPERT Find the value of p, for which one root of the quadratic equation px2 – 14x + 8 = 0 is 6 times the other. Let the first root be α, then the second root will be 6α. Sum of roots= `(−b)/a` `=> a + 6a = 14/p` `=> 7a = 14/p` `=> a = 2/p` Product of roots = `c/d` `=> a  xx  6a = 8/p` `=> 6a^2 = 8/p` `=>6(2/p)^2 = 8/p` `=> p = 3` Hence the value of p is 3 Concept: Nature of Roots of a Quadratic Equation  Is there an error in this question or solution? Given quadratic equation is, px² -2√5 px + 15 = 0 Compare px² -2√5 px + 15 = 0 with ax² + bx + c = 0 a = p , b = -2√5p , c = 15 We know that , If the roots of the quadratic equation are equal , then it's discriminant (D) equals to zero.discriminant = 0b² - 4ac = 0( -2√5 p )² - 4× p × 15 = 020p² - 60p = 020p ( p - 3 ) = 0p - 3 = 0p = 3