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How many ways can a committee of three be chosen from a group of ten people? How many ways are there to choose a president, secretary, and treasurer.
I know that on the first part I have to use the combination formula since order doesn't matter. Then $\frac{n!}{r!(n-r)!} \rightarrow \frac{10!}{3!(10-3)!}$= 120.
The second part requires order meaning that I need to use the permutation formula $\frac{n!}{(n-r)!}$ $\rightarrow$ $\frac{10!}{(10-3)!}$ = 720.
Is my process correct?
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