Find two consecutive even integers such that the sum of the larger and 3 times the smaller is 234

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find 3 consecutive integers such that the product of the second and third integer is 20 Take three integers x, y, and z. The for xyz, we want y*z = 20 The factors of 20 are 20*1 10*2 5*4. 20*1 are not consecutive. 10*2 are not

ind two consecutive even integers such that the smaller added to five times the larger is 58

The sum of four consecutive even integers is the same as the least of the integers. Find the integers. I'm not sure how to solve it and put it in an equation!

Algebra.Com
Question 131697This question is from textbook
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what are two consecutive even integers such that the sum of the larger and 3 times the smaller is 234?

This question is from textbook

Found 2 solutions by stanbon, checkley71:Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!

what are two consecutive even integers such that the sum of the larger and 3 times the smaller is 234? --------------- Represent even numbers as "2n" since each is a multiple of 2. Represent odd numbers as "2n+1" since each is one more than an even. ----------------- Your problem: smaller # : 2n larger #: 2n+2 ------------------- EQUATION: 2n+2 + 3(2n) = 234 8n = 232 n = 29 --------- smaller = 2*29 = 58 larger = 2n+2 = 60 ======================= Cheers,

Stan H.

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
x+2+3x=234 4x=2=234 4x=234-2 4x=232 x=232/4 x=58 answer for the smaller even nunmber. 58+2=60 answer for the larger even number. proof: 60+3*58=234 60+174=234
234=234

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