Every square number can be expressed as a sum of successive odd natural numbers starting from 1. So, square root of 256 = 256 - 1 = 255 , 255 - 3 = 252 , 252 - 5 = 247 , 247 - 7 = 240 , 240 - 9 = 231 , 231 - 11 = 220 , 220 - 13 = 207 , 207 - 15 = 192 , 192 - 17 = 175 , 175 - 19 = 156 , 156 - 21 = 135 , 135 - 23 = 112 , 112 - 25 = 87 , 87 - 27 = 60 , 60 - 29 = 31 and finally, 31 - 31 = 0. We had to subtract 16 odd numbers to obtain o. Therefore , this means that 16 is the square root of 256.
in repeated subraction method we have to subtract only odd numbers so our first odd no. is 1 256-1=255 - 3=252 -5=247- 7=240 - 9=231-11=220 -13=207 - 15=192 -17=175 -19=156 -21=135 -23=112 -25=87-27=60 -29=31 -31=0 now in total we subtracted 16 odd numbers.So,16 is the square root of 256 Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Suggest Corrections 1 |