Free
60 Questions 120 Marks 50 Mins
Given:
6, 7, 8, 9, and 12.
Concept used:
The least common multiple (LCM) of a set of numbers is the smallest number that leaves 0 as the remainder each time when divided by any of those numbers.
Calculation:
LCM (6, 7, 8, 9 12) = 504
So, 504 is the smallest number that leaves 0 as the remainder each time when divided by any of 6, 7, 8, 9, and 12.
So, the required number = (504 + 2) = 506
∴ 506 will be the smallest number which when divided by 6, 7, 8, 9, and 12 leaves the remainder 2 each time.
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Get Started for Free Download App
Trusted by 3.4 Crore+ Students