At what time will train running at speed 80 kmph of length 200 Metres will cross a tree of length 40 Metres?

Exercise :: Problems on Trains - General Questions

11. 

A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?

A. 230 m
B. 240 m
C. 260 m
D. 320 m
E. None of these

Answer: Option A

Explanation:

Relative speed = (120 + 80) km/hr

   =
200 x 5
m/sec
18

   =
500
m/sec.
9

Let the length of the other train be x metres.

x + 270 = 500

x = 230.

View Answer Discuss in Forum Workspace Report

12. 

A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?

A. 230 m
B. 240 m
C. 260 m
D. 270 m

Answer: Option D

Explanation:

Speed =
72 x 5
m/sec
= 20 m/sec.
18

Time = 26 sec.

Let the length of the train be x metres.

x + 250 = 520

x = 270.

View Answer Discuss in Forum Workspace Report

Page 2

Exercise :: Problems on Trains - General Questions

View Answer Discuss in Forum Workspace Report

17. 

A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:

Answer: Option C

Explanation:

Speed =
78 x 5
m/sec =
65
m/sec.
18 3

Time = 1 minute = 60 seconds.

Let the length of the tunnel be x metres.

Then,
800 + x
= 65
60 3

3(800 + x) = 3900

x = 500.

View Answer Discuss in Forum Workspace Report

Page 3

Exercise :: Problems on Trains - General Questions

View Answer Discuss in Forum Workspace Report

22. 

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

A. 12 sec
B. 24 sec
C. 48 sec
D. 60 sec

Answer: Option B

Explanation:

Relative speed = = (45 + 30) km/hr
=
75 x 5
m/sec
18
=
125
m/sec.
6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Required time =
500 x 6
= 24 sec.
125

View Answer Discuss in Forum Workspace Report

Page 4

Exercise :: Problems on Trains - General Questions

View Answer Discuss in Forum Workspace Report

27. 

A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:

A. 45 m
B. 50 m
C. 54 m
D. 72 m

Answer: Option B

Explanation:

2 kmph =
2 x 5
m/sec = 5 m/sec.
18 9

4 kmph =
4 x 5
m/sec = 10 m/sec.
18 9

Let the length of the train be x metres and its speed by y m/sec.

Then,
x
= 9 and
x
= 10.

9y - 5 = x and 10(9y - 10) = 9x

9y - x = 5 and 90y - 9x = 100.

On solving, we get: x = 50.

Length of the train is 50 m.

View Answer Discuss in Forum Workspace Report

28. 

A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?

A. 66 km/hr
B. 72 km/hr
C. 78 km/hr
D. 81 km/hr

Answer: Option D

Explanation:

4.5 km/hr =
4.5 x 5
m/sec = 5 m/sec = 1.25 m/sec, and
18 4

5.4 km/hr =
5.4 x 5
m/sec = 3 m/sec = 1.5 m/sec.
18 2

Let the speed of the train be x m/sec.

Then, (x - 1.25) x 8.4 = (x - 1.5) x 8.5

8.4x - 10.5 = 8.5x - 12.75

0.1x = 2.25

x = 22.5

Speed of the train =
22.5 x 18
km/hr = 81 km/hr.
5

Page 5

Exercise :: Problems on Trains - General Questions

View Answer Discuss in Forum Workspace Report

Neuester Beitrag

Stichworte