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Tardigrade - CET NEET JEE Exam App
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Text Solution
80 K`-73 K`3 K20 K
Answer : D
Solution : `upsilon_(rms) = sqrt((3RT_(H))/(M_H)) = sqrt((3RT_("OXY"))/(M_("OXY"))` <br> `(T_H)/(M_H) = (T_("OXY"))/(M_("OXY"))` <br> or, `T_(H) = T_("OXY") (M_H)/(M_("OXY")) = (47+273) 2/32 = 320/16` <br> `= 20K`.
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At what temperature is the rms velocity of a hydrogen molecule equal to that of an oxygen molecule at 47∘ CA. 80 KB. 73 KC. 3 KD. 20 K
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