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Answered by Guest on 2018-01-20 03:14:23 | Votes 32 | #
Let the CP of article A be Rs.x
CP of article B = Rs.(5000 - x)
According to the question,
120% of x + 90% of (5000 - x) = 102% of 5000
120x + 450000 - 90x = 510000
30x = 510000 - 450000 = 60000
x = 6000 / 30
= Rs.2000
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Questions : A person bought two articles A and B for Rs.5,000. He sold A at 20% profit and B at 10% loss. He thus gained 2% on his outlay. The cost price of A was
(a) Rs.3,500
(b) Rs.2,000
(c) Rs.2,500
(d) Rs.3,000
Answer: (b)
Let the CP of article A be Rs.x
CP of article B = Rs.(5000 - x)
According to the question,
120% of x + 90% of (5000 - x) = 102% of 5000
120x + 450000 - 90x = 510000
30x = 510000 - 450000 = 60000
x = $60000/30$ = Rs.2000
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Correct Answer:
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According to question,
CP of A = Rs. 2000.
Part of solved Profit and Loss questions and answers : >> Aptitude >> Profit and Loss
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Home » Aptitude » Profit and Loss » Question
-
A person bought two articles A and B for $ 5,000. He sold A at 20% profit and B at 10% loss. He thus gained 2% on his outlay. The cost price of A was
-
- $ 3,000
- $ 2,500
- $ 2,000
- $ 3,500
Given that , CP of two articles A and B = $ 5,000Let the CP of article A be $ y∴ CP of article B = $ (5000 – y)According to the question,120% of y + 90% of (5000 – y) = 102% of 5000⇒ 120y + 450000 – 90y = 510000⇒ 30y = 510000 – 450000 = 60000
Hence , The cost price of A is $ 2000 .